AP EAMCET · PHYSICS · Current Electricity
A copper wire of radius \(0.1 \mathrm{~mm}\) and resistance \(2 \mathrm{k} \Omega\) is connected across a power supply of \(40 \mathrm{~V}\). The number of electrons transferred per second between the supply and the wire at one end is
- A \(2.00 \times 10^{16}\)
- B \(1.25 \times 10^{17}\)
- C \(2.85 \times 10^{17}\)
- D \(3.25 \times 10^{16}\)
Answer & Solution
Correct Answer
(B) \(1.25 \times 10^{17}\)
Step-by-step Solution
Detailed explanation
Radius of copper wire, \(r=0.1 \mathrm{~mm}\) \(=1 \times 10^{-4} \mathrm{~m}\) Resistance, \(R=2 \mathrm{k} \Omega=2 \times 10^3 \Omega\) Power supply, \(V=40 \mathrm{~V}\) Current flowing through the wire, \(I=\frac{V}{R}=\frac{40}{2 \times 10^3}=2 \times 10^{-2} \mathrm{~A}\)…
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