AP EAMCET · PHYSICS · Electrostatics
The maximum potential energy due to electrostatic repulsion between two hydrogen nucleus is nearly (radius of the nucleus Fermi)
- A
- B
- C
- D
Answer & Solution
Correct Answer
(A)
Step-by-step Solution
Detailed explanation
The separation between two hydrogen nucleus should be equal to the diameter of nucleus, ⇒r=2r0=2×1.1×10-15 m so potential energy of the system, U=14πε0q1q2r=9×109×1.6×10-1922×1.1×10-15=0.65 MeV
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