AP EAMCET · PHYSICS · Current Electricity
The bulb which glows with maximum intensity in the given circuit is
- A \(4 \Omega\) bulb
- B \(2 \Omega\) bulb
- C \(3 \Omega\) bulb
- D \(6 \Omega\) bulb
Answer & Solution
Correct Answer
(A) \(4 \Omega\) bulb
Step-by-step Solution
Detailed explanation
Given circuit is As, resistance of portion \(B\) is higher. \(\therefore\) A greater potential drop across \(B\) occurs. Now, in section \(B\), Power, \(P=\frac{V^2}{R}\) So, least resistance gives a higher power output. \(\therefore 4 \Omega\) bulb glows with maximum intensity.
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