AP EAMCET · PHYSICS · Magnetic Effects of Current
In a crossed field, the magnetic field induction is \(2.0 \mathrm{~T}\) and electric field intensity is \(20 \times 10^3 \mathrm{~V} / \mathrm{m}\). At which velocity the electron will travel in a straight line without the effect of electric and magnetic fields?
- A \(\frac{20}{16} \times 10^3 \mathrm{~ms}^{-1}\)
- B \(10 \times\ 10^3\ ms^{-1}\)
- C \(20 \times\ 10^3\ ms^{-1}\)
- D \(40 \times\ 10^3\ ms^{-1}\)
Answer & Solution
Correct Answer
(B) \(10 \times\ 10^3\ ms^{-1}\)
Step-by-step Solution
Detailed explanation
\(e V B=e E\) where, \(e=\) electronic charge and \(v=\) velocity of electron \(\Rightarrow \quad v=\frac{E}{B} v=\frac{20 \times 10^3}{2.0}=10 \times 10^3 \mathrm{~ms}^{-1}\)
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