AP EAMCET · PHYSICS · Semiconductors
The base current in a transistor circuit changes from \(45 \mu \mathrm{A}\) to \(140 \mu \mathrm{A}\). Accordingly, the collector current changes from \(0.2 \mathrm{~mA}\) to \(0.400 \mathrm{~mA}\). The gain in current is
- A \(9.5\)
- B \(1\)
- C \(40\)
- D \(20\)
Answer & Solution
Correct Answer
(C) \(40\)
Step-by-step Solution
Detailed explanation
\begin{aligned} & \text { Current gain } \beta=\frac{\Delta i_c}{\Delta i_b} \\ & \Delta i_c=(4-0.2) \mathrm{mA}=3.8 \times 10^{-3} \mathrm{~A} \\ & \Delta i_b=(140-45) \mu \mathrm{A}=95 \times 10^{-6} \mathrm{~A} \\ & \therefore \quad \beta=\frac{3.8 \times 10^{-3}}{95 \times…
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