AP EAMCET · PHYSICS · Oscillations
The angular frequency of a block of mass 0.1 kg oscillating with the help of a spring of force constant \(2.5 \mathrm{Nm}^{-1}\) is
- A \(0.2 \mathrm{~rad~} \mathrm{s}^{-1}\)
- B \(5 \mathrm{~rad~} \mathrm{s}^{-1}\)
- C \(10 \mathrm{~rad~} \mathrm{s}^{-1}\)
- D \(2 \mathrm{~rad~} \mathrm{s}^{-1}\)
Answer & Solution
Correct Answer
(B) \(5 \mathrm{~rad~} \mathrm{s}^{-1}\)
Step-by-step Solution
Detailed explanation
\(\omega = \sqrt{\frac{k}{m}}\) \(\omega = \sqrt{\frac{2.5 \mathrm{~Nm^{-1}}}{0.1 \mathrm{~kg}}}\) \(\omega = 5 \mathrm{~rad~} \mathrm{s}^{-1}\)
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