AP EAMCET · PHYSICS · Electrostatics
The electric field intensity at a point on the axis of an electric dipole in air is \(4 \mathrm{NC}^{-1}\). Then the electric field intensity at a point on the equatorial line which is at a distance equal to twice the distance on the axial line and if the dipole is in a medium of dielectric constant 4 is
- A \(1 \mathrm{NC}^{-1}\)
- B \(\frac{1}{8} \mathrm{NC}^{-1}\)
- C \(16 \mathrm{NC}^{-1}\)
- D \(\frac{1}{16} \mathrm{NC}^{-1}\)
Answer & Solution
Correct Answer
(D) \(\frac{1}{16} \mathrm{NC}^{-1}\)
Step-by-step Solution
Detailed explanation
As, electric field intensity on the axis, \( \begin{aligned} E_{\text {axis }}=\frac{2 k P}{r^3} \Rightarrow 4=\frac{2 k P}{r^3} \text { for } r & >a \\ & \left(\because \text { given, } E_{\text {axis }}=4\right) \end{aligned} \) \(\Rightarrow \quad \frac{k P}{r^3}=2\) ...(i)…
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