AP EAMCET · Maths · Probability
Suppose that a book of 600 pages contains 40 print mistakes. Assume that these errors are randomly distributed throughout the book and the number of errors per page follows a Poisson distribution. The probability that all the 10 pages selected at random with no print mistakes is
- A \(\frac{1}{3} e^{-1}\)
- B \(2 e^{-1 / 3}\)
- C \(e^{-2 / 3}\)
- D \(\frac{1}{3} e^{-2}\)
Answer & Solution
Correct Answer
(C) \(e^{-2 / 3}\)
Step-by-step Solution
Detailed explanation
Assuming errors are randomly distributed throughout the book and \(x\), the number of errors per page has a poisson distribution \(P(X=x)=\frac{e^{-\lambda} \lambda^x}{x !}(x=0,1,2, \ldots\). Probability of mistakes \(=\frac{40}{600}=\frac{1}{15}\) Mean…
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