AP EAMCET · Chemistry · p Block Elements (Group 15, 16, 17 & 18)
The pair of xenon compounds which have same number of lone pairs of electrons on the central atom is
- A \(\mathrm{XeO}_3, \mathrm{XeF}_6\)
- B \(\mathrm{XeF}_2, \mathrm{XeF}_4\)
- C \(\mathrm{XeF}_4, \mathrm{XeO}_3\)
- D \(\mathrm{XeF}_4, \mathrm{XeOF}_4\)
Answer & Solution
Correct Answer
(A) \(\mathrm{XeO}_3, \mathrm{XeF}_6\)
Step-by-step Solution
Detailed explanation
Xe has 6 of its electrons in bonding with one lone pair, i.e. Xe will have 2 non-bonding electrons. In \(\mathrm{XeF}_6\) Xe has 6 of its electrons in bonding with F. So, Xe will have 2 non-bonding electrons, i.e. 1 lone pair.
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