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AP EAMCET · PHYSICS · Motion In One Dimension

The acceleration at the end of 2 s, of a particle whose motion is represented by the equation S=4t3-8t2+5t+4 is ______

  1. A 32 m s-2
  2. B 40 m s-2
  3. C 37 m s-2
  4. D 35 m s-2
Verified Solution

Answer & Solution

Correct Answer

(A) 32 m s-2

Step-by-step Solution

Detailed explanation

Given that displacement S=4t3-8t2+5t+4 velocity v=dSdt ⇒v=d4t3-8t2+5t+4dt ⇒v=12t2-16t+5 acceleration a=dvdt ⇒a=d12t2-16t+5dt ⇒a=24t-16 so acceleration at t=2  a=242-16=32 m s-2