AP EAMCET · PHYSICS · Magnetic Effects of Current
A cyclotron's oscillator frequency is \(20 \mathrm{MHz}\). The operating magnetic field for accelerating protons is (charge of proton \(=1.6 \times 10^{-19} \mathrm{C}\), mass of proton \(=1.67\) \(\left.\mathrm{x} 10^{-27} \mathrm{~kg}\right)\)
- A \(0.66 \mathrm{~T}\)
- B \(1.1 \mathrm{~T}\)
- C \(0.33 \mathrm{~T}\)
- D \(1.31 \mathrm{~T}\)
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Correct Answer
(D) \(1.31 \mathrm{~T}\)
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