AP EAMCET · PHYSICS · Electromagnetic Induction
A rod of length \(1.0 \mathrm{~m}\) is rotated in a plane perpendicular to a uniform magnetic field of induction \(0.25 \mathrm{~T}\) with a frequency of \(12 \mathrm{rev} / \mathrm{s}\). The induced emf across the ends to the rod is
- A \(18.89 \mathrm{~V}\)
- B \(3 \mathrm{~V}\)
- C \(15 \mathrm{~V}\)
- D \(9.42 \mathrm{~V}\)
Answer & Solution
Correct Answer
(D) \(9.42 \mathrm{~V}\)
Step-by-step Solution
Detailed explanation
Length of rod, \(l=1.0 \mathrm{~m}\)…
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