AP EAMCET · Maths · Circle
A circle \(S=0\) with radius \(\sqrt{2}\) touches the line \(x+y-2=0\) at \((1,1)\). Then, the length of the tangent drawn from the point \((1,2)\) to \(S=0\) is
- A 1
- B \(\sqrt{2}\)
- C \(\sqrt{3}\)
- D 2
Answer & Solution
Correct Answer
(C) \(\sqrt{3}\)
Step-by-step Solution
Detailed explanation
Equation of line at \((1,1)\) is \(x+y-2=0\) Slope of this line is -1 . So, slope of line perpendicular to this line is 1 . \(\therefore \quad \tan \theta=1 \quad \theta=\frac{\pi}{4}\) Let, centre of circle \((h, k)\) i.e. \(x=h \pm r \cos \theta\) and \(y=k \pm r \sin \theta\)…
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