AP EAMCET · PHYSICS · Work Power Energy
Potential energy of a body of mass \(1 \mathrm{~kg}\) free to move along \(X\)-axis is given by \(U(x)=\left(\frac{x^2}{2}-x\right) J\). If the total mechanical energy of the body is \(2 \mathrm{~J}\), then the maximum speed of the body is (Assume only conservative force acts on the body)
- A \(\sqrt{5} \mathrm{~ms}^{-1}\)
- B \(5 \mathrm{~ms}^{-1}\)
- C \(3.5 \mathrm{~ms}^{-1}\)
- D \(\sqrt{8} \mathrm{~ms}^{-1}\)
Answer & Solution
Correct Answer
(A) \(\sqrt{5} \mathrm{~ms}^{-1}\)
Step-by-step Solution
Detailed explanation
Key Idea Total mechanical energy of a system is the addition of potential and kinetic energy \[ E=U+\mathrm{KE} \] Here, mass of the body, \(m=1 \mathrm{~kg}\), \[ E_{\text {mech }}=2 \mathrm{~J} \] So, for…
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