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AP EAMCET · PHYSICS · Motion In One Dimension

A biker travels \(\frac{1}{3}\) of the distance \(L\) with speed \(v_1\) and \(\frac{2}{3}\) of the distance with speed \(v_2\). Then the average speed is

  1. A \(\frac{v_1 v_2}{v_1+v_2}\)
  2. B \(\frac{3 v_1 v_2}{2 v_1+v_2}\)
  3. C \(\frac{3 v_1 v_2}{v_1+2 v_2}\)
  4. D \(\frac{v_1+v_2}{v_1 v_2}\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(\frac{3 v_1 v_2}{2 v_1+v_2}\)

Step-by-step Solution

Detailed explanation

The given situation is shown below Average speed \(=\frac{\text { Total distance }}{\text { Time taken }}\) In given situation time to cover first part, \(t_1=\frac{L / 3}{v_1}=\frac{L}{3 v_1}\) \((\therefore\) Time \(=\) Distance \(/\) Speed \()\) and time to cover second part…
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