AP EAMCET · PHYSICS · Mechanical Properties of Solids
Two equal and op po site forces each Fact on
a rod of uniform cross-sectional area a as
shown in the figure. Shearing stress on the
section AB will be
- A \(\frac{F \sin \theta \cos \theta}{a}\)
- B \(\frac{F \sin \theta}{a}\)
- C \(\frac{F \cos \theta}{a}\)
- D \(\frac{F \sin ^2 \theta}{a}\)
Answer & Solution
Correct Answer
(A) \(\frac{F \sin \theta \cos \theta}{a}\)
Step-by-step Solution
Detailed explanation
Shearing stress \[ \begin{aligned} & =-\frac{F \sin \theta}{a_x} \\ & =-\frac{F}{a} \sin \theta \cos \theta \end{aligned} \] Magnitude of shearing stress \[ =\frac{F}{a} \sin \theta \cos \theta \]
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