AP EAMCET · PHYSICS · Kinetic Theory of Gases
Under standard conditions, the density of a gas is \(\frac{1400}{1089} \mathrm{~kg} \mathrm{-} \mathrm{m}^{-3}\) and the speed of sound propagation in it is \(330 \mathrm{~ms}^{-1}\), then the number of degrees of freedom of the gas molecules is
- A 2
- B 7
- C 5
- D 3
Answer & Solution
Correct Answer
(C) 5
Step-by-step Solution
Detailed explanation
Given, density of gas, \(\rho=\frac{1400}{1089} \mathrm{~kg} / \mathrm{m}^3\) speed of sound, \(v=330 \mathrm{~m} / \mathrm{s}\) and under standard condition, Pressure of gas, \(p=1 \times 10^5 \mathrm{~N} / \mathrm{m}^2\) If \(\gamma\) be the ratio of \(C_p\) and \(C_V\) of a…
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