AP EAMCET · Maths · Probability

A discrete random variable $X$ takes values $10, 20, 30$ and $40$ , with probability $0.3, 0.3, 0.2, 0.2$ respectively. Then the expected value of $X$ is

A $12$
B $22$
C $23$
D $24$

Verified Solution

Answer & Solution

Correct Answer

(C) $23$

Step-by-step Solution

Detailed explanation

Expected value of X is given by ∑XP(X), where P(X) is probability of random variable X. ⇒∑XP(X)=10×0.3+20×0.3+30×0.2+40×0.2 =3+6+6+8=23

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

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A discrete random variable X takes values 10,20,30 and 40, with probability 0.3,0.3,0.2,0.2 respectively. Then the expected value of X is

Step-by-step Solution

A discrete random variable $X$ takes values $10, 20, 30$ and $40$ , with probability $0.3, 0.3, 0.2, 0.2$ respectively. Then the expected value of $X$ is