AP EAMCET · PHYSICS · Oscillations
Time period of a simple pendulum in Air is T. If the pendulum is in water and executes SHM, its time period is \(t\). The value of \(\frac{\mathrm{T}}{t}\) is [density of bob is \(\frac{5000}{3} \mathrm{~kg} \mathrm{~m}^{-3}\) ]
- A \(\frac{2}{5}\)
- B \(\sqrt{\frac{2}{5}}\)
- C \(\frac{5}{2}\)
- D \(\sqrt{\frac{5}{2}}\)
Answer & Solution
Correct Answer
(B) \(\sqrt{\frac{2}{5}}\)
Step-by-step Solution
Detailed explanation
For simple pendulum Time period in air, \(\mathrm{T}=2 \pi \sqrt{\frac{1}{\mathrm{~g}}}\) ...(i) Time period in water, \(\mathrm{T}=2 \pi \sqrt{\frac{1}{\mathrm{~g}\left(1-\frac{\delta}{\sigma}\right)}}\)…
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