AP EAMCET · Chemistry · Haloalkanes and Haloarenes
Chlorobenzene ( X ) when reacted with reagent ' \(A\) ' gets converted to phenol (Y). The major product obtained from nitration of \(X\) gets converted to p-nitrophenol \((\mathrm{Z})\) by reaction with reagent B . What are A and B respectively?
- A \(\begin{aligned} & \mathrm{A}=\text { = (i) } \mathrm{NaOH}, 623 \mathrm{~K}, 300 \mathrm{~atm} \text { (ii) } \mathrm{H}^{+} ; \\ & \mathrm{B}=\text { (i) } \mathrm{NaOH}, 443 \mathrm{~K} \text { (ii) } \mathrm{H}^{+}\end{aligned}\)
- B \(\begin{aligned} & \mathrm{A}=\text { (i) } \mathrm{NaOH}, 443 \mathrm{~K} \text { (ii) } \mathrm{H}^{+} ; \\ & \mathrm{B}=\mathrm{H}_2 \mathrm{O}, \Delta\end{aligned}\)
- C \(\begin{aligned} & \mathrm{A}=\text { (i) } \mathrm{NaOH}, 323 \mathrm{~K} \text { (ii) } \mathrm{H}^{+}: \\ & \mathrm{B}=\text { (i) } \mathrm{NaOH}, 443 \mathrm{~K} \text { (ii) } \mathrm{H}^{+}\end{aligned}\)
- D \(\begin{aligned} & \mathrm{A}=\text { (i) } \mathrm{NaOH}, 623 \mathrm{~K}, 300 \mathrm{~atm} \text { (ii) } \mathrm{H}^{+} ; \\ & \mathrm{B}=\mathrm{H}_2 \mathrm{O}, \Delta\end{aligned}\)
Answer & Solution
Correct Answer
(A) \(\begin{aligned} & \mathrm{A}=\text { = (i) } \mathrm{NaOH}, 623 \mathrm{~K}, 300 \mathrm{~atm} \text { (ii) } \mathrm{H}^{+} ; \\ & \mathrm{B}=\text { (i) } \mathrm{NaOH}, 443 \mathrm{~K} \text { (ii) } \mathrm{H}^{+}\end{aligned}\)
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