AP EAMCET · Maths · Straight Lines
The equation of the perpendicular bisectors of the sides \(A B\) and \(A C\) of a \(\triangle A B C\) are \(x-y+5=0\) and \(x+2 y+5=0\), respectively. If \(A\) is \((1,-2)\), then the equation of the straight line \(B C\) is
- A \(14 x+23 y-40=0\)
- B \(12 x+17 y-28=0\)
- C \(14 x-29 y-30=0\)
- D \(7 x-12 y+15=0\)
Answer & Solution
Correct Answer
(A) \(14 x+23 y-40=0\)
Step-by-step Solution
Detailed explanation
The point \(B\left(x_1, y_1\right)\) is the reflection of point \(A\) w.r.t. line \(x-y+5=0\), so \(\begin{aligned} \Rightarrow \quad \frac{x_1-1}{1} & =\frac{y_1+2}{-1} \\ & =-2 \frac{1+2+5}{2}=-8 \\ \Rightarrow \quad x_1 & =-7, y_1=6 \end{aligned}\) so, \(B(-7,6)\) Similarly…
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