AP EAMCET · PHYSICS · Wave Optics
In Young's double slit experiment, the distance between the slits is 0.2 cm, the distance between the screen and the slits is 1 m. If the wavelength of light used in the experiment is \(5000 Å\), then the distance between two consecutive dark fringes on the screen is
- A 0.25 mm
- B 0.26 mm
- C 0.27 mm
- D 0.28 mm
Answer & Solution
Correct Answer
(A) 0.25 mm
Step-by-step Solution
Detailed explanation
\(\beta = \frac{\lambda D}{d}\) \(\beta = \frac{(5000 \times 10^{-10} \text{ m}) \times (1 \text{ m})}{(0.2 \times 10^{-2} \text{ m})}\) \(\beta = 0.25 \text{ mm}\)
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