AP EAMCET · PHYSICS · Dual Nature of Matter
In a photoelectric experiment, a monochromatic light is incident on the emitter plate \(E\), as shown in the figure. When switch \(S_1\) is closed and switch \(S_2\) is open, the photoelectrons strike the collector plate \(C\) with a maximum kinetic energy of \(1 \mathrm{eV}\). If switch \(S_1\) is open and switch \(S_2\) is closed and the frequency of the incident light is doubled the photoelectrons strike the collector plate with a maximum kinetic energy of \(20 \mathrm{eV}\). The threshold wavelength of the emitter plate is

- A \(5233.3 Å\)
- B \(4133.3 Å\)
- C \(4166.7 Å\)
- D \(5336.7 Å\)
Answer & Solution
Correct Answer
(B) \(4133.3 Å\)
Step-by-step Solution
Detailed explanation
Let threshold frequency of emitter plate \(=v_0\) Energy of photon in first case is \(\mathrm{E}\). When switch \(S_1\) is closed and switch \(S_2\) is open, So, \(E=h v_0+(5+1) \mathrm{eV}\) ...(i) For second case, when switch \(S_1\) is open and switch \(S_2\) is closed and…
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