AP EAMCET · PHYSICS · Alternating Current
An inductor and a resistor are connected in series to an ac source of voltage \(144 \sin \left(100 \pi t+\frac{\pi}{2}\right)\) Volt. If the current in the circuit is \(6 \sin \left(100 \pi t+\frac{\pi}{6}\right)\) ampere, then the resistance of the resistor is
- A \(24 \Omega\)
- B \(36 \Omega\)
- C \(12 \Omega\)
- D \(18 \Omega\)
Answer & Solution
Correct Answer
(C) \(12 \Omega\)
Step-by-step Solution
Detailed explanation
In LR circuit, \(\begin{aligned} & V=144 \sin \left(100 \pi t+\frac{\pi}{2}\right) \\ & I=6 \sin \left(100 \pi t+\frac{\pi}{6}\right) \end{aligned}\) Also, \(\tan \phi=\frac{X_L}{R} \Rightarrow \tan \left(\frac{\pi}{2}-\frac{\pi}{6}\right)=\frac{X_L}{R}\)…
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