AP EAMCET · PHYSICS · Nuclear Physics
A mixture consists of two radioactive materials \(A_1\) and \(A_2\) with half lives of 20 s and 10 s respectively. Initially the mixture has 40 g of \(\mathrm{A}_1\) and 160 g of \(\mathrm{A}_2\). The amount of the two in the mixture will become equal after
- A 60 s
- B 80 s
- C 20 s
- D 40 s
Answer & Solution
Correct Answer
(D) 40 s
Step-by-step Solution
Detailed explanation
For radioactive material \(\mathrm{A}_1\), \(\mathrm{N}_1=\mathrm{N}_{\mathrm{ol}}\left(\frac{1}{2}\right)^{\mathrm{n}}=40\left(\frac{1}{2}\right)^{\mathrm{t}_{1 / 20}}\ldots(i)\) For radioactive material…
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