ExamBro
ExamBro
AP EAMCET · Maths · Application of Derivatives

Tangents are drawn to the curve \(y=\sin x\) from the origin. The locus of the points of contact is

  1. A \(x y=x+y\)
  2. B \(x^2 y^2=x^2-y^2\)
  3. C \(x y=x-y\)
  4. D \(x^2 y^2=x^2+y^2\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(x^2 y^2=x^2-y^2\)

Step-by-step Solution

Detailed explanation

Given, \(y=\sin x\) Differentiating w.r.t. \(x\), we get \(\frac{d y}{d x}=\cos x\) If tangent to \(y=\sin x\) meet at \((h, k)\) \(\left(\frac{d y}{d x}\right)_{(h, k)}=\cos h\) \(\therefore\) Equation of tangent is \(\cos h(x-h)=y-k\) Since, tangent is passing through…