AP EAMCET · PHYSICS · Capacitance
In the given circuit, the potential difference across \(5 \mu \mathrm{~F}\) capacitor is
- A 48 V
- B 24 V
- C 63 V
- D 21 V
Answer & Solution
Correct Answer
(A) 48 V
Step-by-step Solution
Detailed explanation
\(\begin{gathered}C_1=5 \mu \mathrm{~F}, \mathrm{C}_2=(4+8+4)=16 \mu \mathrm{~F} \\ \therefore \mathrm{~V}_1=\left(\frac{\mathrm{C}_2}{\mathrm{C}_1+\mathrm{C}_2}\right) \mathrm{V}=\left(\frac{16}{16+5}\right) 63=48 \mathrm{~V}\end{gathered}\)
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