AP EAMCET · PHYSICS · Center of Mass Momentum and Collision
A mass of \(2.9 \mathrm{~kg}\) is suspended from a string of length \(50 \mathrm{~cm}\) and is at rest. Another body of mass \(100 \mathrm{~g}\), which is moving horizontally with a velocity of \(150 \mathrm{~m} / \mathrm{s}\) strikes and sticks to it. Subsequently when the string makes an angle of \(60^{\circ}\) with the vertical, the tension in the string is \(\left(g=10 \mathrm{~m} / \mathrm{s}^2\right)\)
- A 145 N
- B 135 N
- C 125 N
- D 90 N
Answer & Solution
Correct Answer
(B) 135 N
Step-by-step Solution
Detailed explanation
From law of conservation of momentum, we known,…
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