AP EAMCET · Maths · Pair of Lines
If the pair of lines \(x^2-16 p x y-y^2=0\) and \(x^2-16 q x y-\) \(y^2=0\) are such that each pair bisects the angle between the other pair, then \(\mathrm{pq}=\)
- A \(\frac{-1}{64}\)
- B \(\frac{1}{64}\)
- C \(\frac{-1}{8}\)
- D \(\frac{1}{8}\)
Answer & Solution
Correct Answer
(A) \(\frac{-1}{64}\)
Step-by-step Solution
Detailed explanation
We have, equations of pair of straight lines Now, equations of bisectors of these line are \[ -8 p x^2-2 x y+8 p y^2=0 \] and \(-8 q x^2-2 x y+8 q y^2=0\) According to the given condition in the data, Eqs. (i) and (iv), and Eqs. (ii) and (iii) must be coincident. So,…
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