AP EAMCET · PHYSICS · Waves and Sound
Two wires \(A\) and \(B\) of lengths in the ratio \(1: 2\) and masses in the ratio \(2: 1\) are stretched by same tension. The ratio of the fundamental frequencies of wires \(A\) and \(B\) is
- A \(2 \sqrt{2}: 1\)
- B \(1: \sqrt{2}\)
- C \(1: 1\)
- D \(\sqrt{2}: 1\)
Answer & Solution
Correct Answer
(C) \(1: 1\)
Step-by-step Solution
Detailed explanation
Fundamental frequency in a stretched wire is given as, \(f=\frac{1}{2 L} \sqrt{\frac{T}{\mu}}\) Ratio of fundamental frequencies of wire \(A\) and \(B\),…
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