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AP EAMCET · Maths · Probability

A random variable \(X\) takes values \(0,1,2,3, \ldots\) with probability \(P(X=x)=K(x+1)\left(\frac{1}{5}\right)^x\), where \(K\) is constant, then \(P(X=0)\) is

  1. A \(\frac{7}{25}\)
  2. B \(\frac{18}{25}\)
  3. C \(\frac{16}{25}\)
  4. D \(\frac{13}{25}\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(\frac{16}{25}\)

Step-by-step Solution

Detailed explanation

Given, \(P(X=x)=K(x+1)\left(\frac{1}{5}\right)^x\) To find, \(P(X=0)\) Since sum of all the probabilities in a probability distribution is 1 . \(\therefore \quad P(X=0)+P(X=1)+P(X=2)+\ldots=1\)…
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