AP EAMCET · PHYSICS · Laws of Motion
In the arrangement shown in the figure, if the blocks of masses \(m\) and \(2 m\) are released from the state of rest, tension in the string is ( \(\mu=\) coefficient of friction, string is massless and inextensible, pulley is frictionless)
- A mg
- B \(\sqrt{2} m g\)
- C \(\frac{2 \sqrt{2} m g}{3}\)
- D \(\frac{\sqrt{2} m g}{3}\)
Answer & Solution
Correct Answer
(C) \(\frac{2 \sqrt{2} m g}{3}\)
Step-by-step Solution
Detailed explanation
Let \(N_1, N_2\) are normal reaction force and \(f_1, f_2\) are the friction force on two blocks. acceleration is \(a\) and tension is \(T\). The respective FBD Friction force, \(f_1=\mu N_1, f_2=\mu N_2\) As,…
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