AP EAMCET · PHYSICS · Kinetic Theory of Gases
If the average kinetic energy of a gas molecule at \(27^{\circ} \mathrm{C}\) is \(3.3 \times 10^{-20} \mathrm{~J}\), then the average kinetic energy of the gas molecules at \(127^{\circ} \mathrm{C}\) is
- A \(15 \times 10^{-20} \mathrm{~J}\)
- B \(0.68 \times 10^{-20} \mathrm{~J}\)
- C \(4.4 \times 10^{-20} \mathrm{~J}\)
- D \(10.3 \times 10^{-21} \mathrm{~J}\)
Answer & Solution
Correct Answer
(C) \(4.4 \times 10^{-20} \mathrm{~J}\)
Step-by-step Solution
Detailed explanation
Average kinetic energy of a gas is given by…
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