AP EAMCET · PHYSICS · Ray Optics
In Ramsden eyepiece, the two planoconvex lenses each of focal length \(f\) are separated by a distance \(12 \mathrm{~cm}\). The equivalent focal length (in \(\mathrm{cm}\) ) of the eyepiece is
- A \(10.5\)
- B \(12.0\)
- C \(13.5\)
- D \(15.5\)
Answer & Solution
Correct Answer
(C) \(13.5\)
Step-by-step Solution
Detailed explanation
\(d=\frac{2 f}{3}\) \(f=\frac{3 d}{2}=\frac{3 \times 12}{2}=18 \mathrm{~cm}\) Equivalent focal length is \(\begin{aligned} f^{\prime} & =\frac{f_1 f_2}{f_1+f_2}+\frac{f}{4}=\frac{18 \times 18}{18+18}+\frac{18}{4} \\ & =9+4.5 \\ & =13.5 \mathrm{~cm}\end{aligned}\)
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