AP EAMCET · Maths · Vector Algebra
Let \(\overrightarrow{\mathrm{OA}}=\hat{\mathrm{i}}+2 \hat{\mathrm{j}}-2 \hat{\mathrm{k}}\) and \(\overrightarrow{\mathrm{OB}}=-2 \hat{\mathrm{i}}-3 \hat{\mathrm{j}}+6 \hat{\mathrm{k}}\) be the position vectors of two points \(A\) and \(B\). If \(C\) is a point on the bisector \(\angle \mathrm{AOB}\) and \(\mathrm{OC}=\sqrt{42}\), then \(\overrightarrow{\mathrm{OC}}=\)
- A \(4 \hat{\mathrm{i}}-\hat{\mathrm{j}}+5 \hat{\mathrm{k}}\)
- B \(\hat{i}+5 \hat{j}+4 \hat{k}\)
- C \(5 \hat{i}+4 \hat{j}+\hat{k}\)
- D \(\hat{i}-4 \hat{j}+5 \hat{k}\)
Answer & Solution
Correct Answer
(B) \(\hat{i}+5 \hat{j}+4 \hat{k}\)
Step-by-step Solution
Detailed explanation
Given \(\overrightarrow{O A}=\vec{i}+2 \vec{j}-2 \vec{k}\) and \(\overrightarrow{O B}=-2 \vec{i}-3 \vec{j}+6 \vec{k}\) Now unit vector bisector \(\angle A O B\)…
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