AP EAMCET · PHYSICS · Thermal Properties of Matter
If a body cools from a temperature of \(62^{\circ} \mathrm{C}\) to \(50^{\circ} \mathrm{C}\) in 10 minutes and to \(42^{\circ} \mathrm{C}\) in the next 10 minutes, then the temperature of the surroundings is
- A \(12^{\circ} \mathrm{C}\)
- B \(26^{\circ} \mathrm{C}\)
- C \(36^{\circ} \mathrm{C}\)
- D \(21^{\circ} \mathrm{C}\)
Answer & Solution
Correct Answer
(B) \(26^{\circ} \mathrm{C}\)
Step-by-step Solution
Detailed explanation
\( \frac{62-50}{10} = K \left( \frac{62+50}{2} - T_s \right) \) \( 1.2 = K(56 - T_s) \quad (1) \) \( \frac{50-42}{10} = K \left( \frac{50+42}{2} - T_s \right) \) \( 0.8 = K(46 - T_s) \quad (2) \) \( \frac{1.2}{0.8} = \frac{56 - T_s}{46 - T_s} \)…
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