AP EAMCET · PHYSICS · Electrostatics
In a region, the intensity of an electric field is given by \(\overrightarrow{\mathrm{E}}=(2 \hat{\mathrm{i}}+3 \hat{\mathrm{j}}+\hat{\mathrm{k}}) \mathrm{NC}^{-1}\). The electric flux through a surface of area \(10 \hat{\mathrm{i}} \mathrm{m}^2\) in the region is
- A \(5 \mathrm{Nm}^2 \mathrm{C}^{-1}\)
- B \(10 \mathrm{Nm}^2 \mathrm{C}^{-1}\)
- C \(15 \mathrm{Nm}^2 \mathrm{C}^{-1}\)
- D \(20 \mathrm{Nm}^2 \mathrm{C}^{-1}\)
Answer & Solution
Correct Answer
(D) \(20 \mathrm{Nm}^2 \mathrm{C}^{-1}\)
Step-by-step Solution
Detailed explanation
An electric flux is given by \(\overrightarrow{\mathrm{E}}=(2 \hat{\mathrm{i}}+3 \hat{\mathrm{j}}+\hat{\mathrm{k}}) \mathrm{N} / \mathrm{C}\) Surface of area, \(\vec{A}=10 \hat{i} \mathrm{~m}^2\) Electric flux is given by…
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