AP EAMCET · Maths · Quadratic Equation
If \(\alpha\) and \(\beta\) are the roots of \(x^2+7 x+3=0\) and \(\frac{2 \alpha}{3-4 \alpha}, \frac{2 \beta}{3-4 \beta}\) are the roots of \(a x^2+b x+c=0\) and GCD of \(a, b, c\) is 1 , then \(a+b+c=\)
- A 11
- B 0
- C 243
- D 81
Answer & Solution
Correct Answer
(D) 81
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & \text {Let } \frac{2 \alpha}{3-4 \alpha}=y \Rightarrow 2 \alpha=3 y-4 \alpha y \\ & \Rightarrow \alpha(2+4 y)=3 y \Rightarrow \alpha=\frac{3 y}{2+4 y} \end{aligned}\) \(\because \alpha\) is root of quadratic equation \(x^2+7 x+3=0\), So,…
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