AP EAMCET · PHYSICS · Electromagnetic Waves
In a plane electromagnetic wave, the electric field oscillates with a frequency \(2 \times 10^{10} \mathrm{~s}^{-1}\) and amplitude \(40 \mathrm{Vm}^{-1}\), then the energy density due to electric field is \(\left(\varepsilon_0=8.85 \times 10^{-12} \mathrm{Fm}^{-1}\right)\)
- A \(1.52 \times 10^{-9} \mathrm{Jm}^{-3}\)
- B \(2.54 \times 10^{-19} \mathrm{Jm}^{-3}\)
- C \(3.54 \times 10^{-9} \mathrm{Jm}^{-3}\)
- D \(4.56 \times 10^{-9} \mathrm{Jm}^{-3}\)
Answer & Solution
Correct Answer
(C) \(3.54 \times 10^{-9} \mathrm{Jm}^{-3}\)
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Detailed explanation
Energy density due to electric field is…
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