ExamBro
ExamBro
AP EAMCET · Chemistry · Structure of Atom

The energy associated with Bohr's orbit in the hydrogen atom is given by the expression, \(E_n=-\frac{13.6}{n^2} \mathrm{eV}\). The energy in \(\mathrm{eV}\) associated with the orbit having a radius \(9 r_1\) is ( \(r_1\) is the radius of the first orbit)

  1. A -13 6
  2. B -6.8
  3. C -1.51
  4. D -1.36
Verified Solution

Answer & Solution

Correct Answer

(C) -1.51

Step-by-step Solution

Detailed explanation

Given, Energy associated with Bohr's orbit in the hydrogen atom \(E_n=-\frac{13.6}{n^2} \mathrm{eV}\) Now, radius of Bohr's orbit, \(r_n=0.529 \frac{n^2}{Z} Å\) or \(r_n=r_1 n^2\) \([\because Z=1\) for hydrogen \(]\) Given, or \(r_n=9 r_1\) \(r_1 n^2=r_1 9\) or \(n^2=9\) or…