AP EAMCET · PHYSICS · Wave Optics
If the ratio of amplitudes of two interfering waves is \(4: 3\), then the ratio of maximum and minimum intensity is
- A \(16: 18\)
- B \(18: 16\)
- C \(49: 1\)
- D \(94: 1\)
Answer & Solution
Correct Answer
(C) \(49: 1\)
Step-by-step Solution
Detailed explanation
Given, the ratio of amplitudes of two interfering waves is \(4: 3\) i.e \(\frac{A_1}{A_2}=\frac{4}{3}\) ...(i) We know that, intensity of wave is proportional to square of amplitude. \(\therefore \frac{I_{\max }}{I_{\min }}=\left(\frac{A_{\max }}{A_{\min }}\right)^2\), where…
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