AP EAMCET · Chemistry · Ionic Equilibrium
\(1 \mathrm{~L}\) of \(0.02 \mathrm{M}\) aqueous \(\mathrm{HCl}\) is mixed with \(1 \mathrm{~L}\) of \(0.01 \mathrm{M}\) aqueous \(\mathrm{H}_2 \mathrm{SO}_4\) solution. Assuming complete dissociation and no change in the volume upon mixing, the \(\mathrm{pH}\) of resultant solution is \(\left(\log _{10} 2=0.3\right)\)
- A 1.7
- B 2.7
- C 3.7
- D 2
Answer & Solution
Correct Answer
(A) 1.7
Step-by-step Solution
Detailed explanation
Given, \(\mathrm{HCl} 1 \mathrm{~L} 0.02 \mathrm{M}\) \[ \mathrm{H}_2 \mathrm{SO}_4 1 \mathrm{~L} 0.01 \mathrm{M} \] Moles of \(\mathrm{H}^{+}\)from \(\mathrm{HCl}=1 \times 0.02=0.02\) Moles of \(\mathrm{H}^{+}\)from \(\mathrm{H}_2 \mathrm{SO}_4=1 \times 0.01 \times 2=0.02\)…
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