AP EAMCET · Maths · Permutation Combination
Let \(l_1\) and \(l_2\) be two lines intersecting at \(P\). If \(A_1, B_1, C_1\) are points on \(l_1\), and \(A_2, B_2, C_2, D_2, E_2\) are points on \(l_2\) and if none of these coincides with \(P\), then the number of triangles formed by these eight points, is :
- A 56
- B 55
- C 46
- D 45
Answer & Solution
Correct Answer
(D) 45
Step-by-step Solution
Detailed explanation
If triangle is formed including point ' \(P\) ' the other points must be one from \(l_1\) and other point from \(l_2\). Number of triangles formed with \(P\), \(n\left(E_1\right)={ }^3 C_1 \times{ }^5 C_1=15 \text { ways }\) When \(P\) is not included, Number of triangles formed…
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