AP EAMCET · PHYSICS · Oscillations
If the displacement ' \(x\) ' of a body in motion in terms of time ' \(t\) ' is given by \(x=A \sin (\omega t+\theta)\), then the minimum time at which the displacement becomes maximum is
- A \(\left[\frac{\pi}{2 \omega}-\frac{\theta}{\omega}\right]\)
- B \(\left[\frac{2 \omega}{\pi}-\frac{\omega}{\theta}\right]\)
- C \(\left[\frac{\pi}{\omega}-\frac{1}{\omega}\right]\)
- D \(\left[\frac{\omega}{\pi}-\frac{\omega}{\pi^2}\right]\)
Answer & Solution
Correct Answer
(A) \(\left[\frac{\pi}{2 \omega}-\frac{\theta}{\omega}\right]\)
Step-by-step Solution
Detailed explanation
\(\sin (\omega t+\theta) = 1\) \(\omega t+\theta = \frac{\pi}{2}\) \(t = \frac{1}{\omega} \left( \frac{\pi}{2} - \theta \right)\) \(t = \left[\frac{\pi}{2 \omega}-\frac{\theta}{\omega}\right]\)
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