AP EAMCET · PHYSICS · Capacitance
Four capacitors are connected as shown in the figure. If \(\mathrm{C}_1, \mathrm{C}_2, \mathrm{C}_3\) and \(\mathrm{C}_4\) are in the ratio of \(1: 2: 3: 4\), then the ratio of the charges on the capacitors \(C_2\) and \(C_4\) is
- A \(1: 4\)
- B \(2: 3\)
- C \(6: 11\)
- D \(3: 22\)
Answer & Solution
Correct Answer
(D) \(3: 22\)
Step-by-step Solution
Detailed explanation
\(C_1=C, C_2=2C, C_3=3C, C_4=4C\) \(\frac{1}{C_{123}} = \frac{1}{C_1} + \frac{1}{C_2} + \frac{1}{C_3} = \frac{1}{C} + \frac{1}{2C} + \frac{1}{3C} = \frac{6+3+2}{6C} = \frac{11}{6C}\) \(C_{123} = \frac{6C}{11}\) \(Q_2 = Q_{123}\) \(V = V_{123} = V_4\)…
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