AP EAMCET · PHYSICS · Work Power Energy
A body of mass \(M\) is dropped from a height \(h\) on a sand floor. If the body penetrates \(x \mathrm{~cm}\) into the sand, then the average resistance offered by the sand to the body is
- A \(M g\left(\frac{h}{x}\right)\)
- B \(M g\left(\frac{x+h}{x}\right)\)
- C \(M g(h+x)\)
- D \(M g\left(\frac{x-h}{x}\right)\)
Answer & Solution
Correct Answer
(B) \(M g\left(\frac{x+h}{x}\right)\)
Step-by-step Solution
Detailed explanation
Given, mass of body \(=M\) Height above the sand floor \(=h\) Distance penetrated into sand \(=x\) Let \(v\) be the velocity with which body strikes the surface. Then, by equation of motion, we get \(v^2=u^2+2 g h \Rightarrow v^2=2 g h\) ...(i) \([\because\) Initial velocity at…
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