AP EAMCET · PHYSICS · Kinetic Theory of Gases
If the degrees of freedom of a gas molecule is 6, then the total internal energy of the gas molecule at a temperature of \(47^{\circ} \mathrm{C~}(\mathrm{in~} \mathrm{eV})\) is
\(\left(\right.\) Boltzmann constant \(\left.=1.38 \times 10^{-23} \mathrm{~J} \mathrm{~K}^{-1}\right)\)
- A \(414 \times 10^{-4}\)
- B \(828 \times 10^{-4}\)
- C \(927 \times 10^{-4}\)
- D \(572 \times 10^{-4}\)
Answer & Solution
Correct Answer
(B) \(828 \times 10^{-4}\)
Step-by-step Solution
Detailed explanation
\(T = 47^{\circ} \mathrm{C} + 273 = 320 \mathrm{~K}\) \(U = \frac{f}{2} k_B T = \frac{6}{2} \times 1.38 \times 10^{-23} \mathrm{~J} \mathrm{~K}^{-1} \times 320 \mathrm{~K} = 1.3248 \times 10^{-20} \mathrm{~J}\)…
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