AP EAMCET · PHYSICS · Electrostatics
A charge \(\mathrm{Q}\) is to be divided between two objects. The values of the charges on the objects so that the electrostatic force between them will be maximum is
- A \(\frac{\mathrm{Q}}{2}, \frac{\mathrm{Q}}{2}\)
- B \(\frac{Q}{3}, \frac{2}{3} Q\)
- C \(\frac{\mathrm{Q}}{4}, \frac{3}{4} \mathrm{Q}\)
- D \(\frac{\mathrm{Q}}{5}, \frac{4}{5} \mathrm{Q}\)
Answer & Solution
Correct Answer
(A) \(\frac{\mathrm{Q}}{2}, \frac{\mathrm{Q}}{2}\)
Step-by-step Solution
Detailed explanation
Let charge on one object be 'q', then on other object it is ' \(\mathrm{Q}-\mathrm{q}^{\prime}\) So, \(\mathrm{F}_{\mathrm{e}}=\frac{\mathrm{K} \mathrm{q}(\mathrm{Q}-\mathrm{q})}{\mathrm{r}^2}\). For \(\mathrm{F}_{\mathrm{e}}\) to be maximum,…
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