AP EAMCET · Maths · Differential Equations
The particular solution of the different equation
\[
\frac{d x}{d y}=\frac{\sin y(1+y \cot y)}{x \log \left(x^2 e\right)}, y(1)=0
\]
- A \(y \sin y=x^2 \log x\)
- B \(y^2 \sin y=\log x\)
- C \(y=\left(\frac{e^2}{\sin e}\right)(x-1)\)
- D \(y=e^2 \sec x\)
Answer & Solution
Correct Answer
(A) \(y \sin y=x^2 \log x\)
Step-by-step Solution
Detailed explanation
\begin{aligned} \text { } & \frac{d x}{d y}=\frac{\sin y(1+y \cot y)}{x \log \left(\mathrm{x}^2 \mathrm{e}\right)}, y(1)=0 \\ \Rightarrow & \int x \log \left(x^2 e\right) d x=\int(\sin y+y \cos y) d y \\ & \text { Let } x^2 e=t \\ \Rightarrow & x d x=\frac{1}{2 e} d t \\…
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