AP EAMCET · PHYSICS · Current Electricity
If the charge on the capacitor is \(1 \mathrm{mC}\) in the given circuit,
then \(\frac{R_1 R_2}{R_3}=\ldots \ldots \ldots . . . . \Omega\).
- A 6
- B 0.4
- C 0.6
- D 10
Answer & Solution
Correct Answer
(C) 0.6
Step-by-step Solution
Detailed explanation
Charge on cap \(=1 \mathrm{mC}\) \( \mathrm{V}_{\text {capacitor }}=\frac{Q}{C}=\frac{1 \times 10^{-3}}{5 \times 10^{-6}}=\frac{1000}{5}=200 \mathrm{~V} \) So, current through \(R_5\) \( I=\frac{V}{R}=\frac{200}{10}=20 \mathrm{~A} \) Hence, we have following current…
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